Resolved complex numbers

Clasified in Problems of Mathematics of Bachelor Degree.

Written at June 23, 2009 on esEspañol, translated to enEnglish and with a size of 189,119 bytes.

1) indicates the real and imaginary part of the following complex numbers
Z1 = (-3.2) / (-3) Real part, (2) Imaginary part
Z2 = (4.1) / (4) Real part, (1) Imaginary part
Z3 = (3, -5) / (3) Real part, (-5) Imaginary part
Z4 = (1 / 2, 0) / (1 / 2) Real part, (0) Imaginary part
Z5 = (0.3) / (0)Real part, (3) Imaginary part
Z6 = (1 / 3, Image ) / (1 / 3) Real part, (-- Image ) Imaginary part

2) Indicates the real and imaginary numbers for the following complex numbers
Z1 = (4.0) = 4
Z2 = (0.5)
= 5 Image
Z3 = (3 / 4, 0) = 3 / 4
Z4 = (0, -5 / 6) = Image


Z5 = (0, Image) = Image
Z6 = ( Image , 0) = Image

3) Put in the form of complex numbers the following real and imagined.

Z1 = 7 = (7.0)
Z2 = Image = (0,3)
Z3 = Image = (0, Image )
Z4 = Image = ( Image , 0)
Z5 = Image = (0, Image
)
Z6 = -3 Image = (-3 Image , 0)

29) Construct the quadratic equation that results in the following roots.
a) x 1 = Image

x 2 Image
Image
Image
b) x 1 = 2 -- Image follows that x 2 = 2 + Image
Image=
Image

c) x 2 = Image follows that x 1 = Image
Image
Image
30) convert the following complex numbers to polar form
a) Image = Image d) Image = Image
ImageImage
ImageImage

b Image = Image
Image
Image

c Image = Image
Image
Image




l calculated following powers in Image
a) Image = Image = 1
b) Image

= Image = 1
c) Image = Image = 1
d) Image = Image = 1
e) Image = Image = Image
f) Image = Image
g) Image = Image

5) Performs the following operations
a) Image
b) Image
C) Image
D) Image
6) calculates (x) and (y) in the following equation.
Image


Image
Image
Image Image
Solution 1 Solution 2
x = 0 and = Imagex = Image And =- 3
Dimensioning Image
This implies that x = 3 can not be used as a so lution.

27) Solve the following equations of Rices imaginary check the solution.

a) 3 Image b) Image
x

1 = Image x 1= Image x 1 = Image
x 2 = Image x 2 = Image x 2 = Image
c) Image
x 1 = Image
x 2 = Image

28) Solve the following quadratic equations and checks.

a) Image
x 1 = Imagex 2 = Image
For x 1
Image
If it holds for xes xes one to two, by transitivity also equals zero.

b) Image
x 1 = Image x 2 = Image
For x1
Image
If it holds for xes xes one to two, by transitivity also equals zero.

Tags:real part imaginary part solution solution
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